(3x+1)(x^2-8x-16)=0

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Solution for (3x+1)(x^2-8x-16)=0 equation: 


Simplifying
(3x + 1)(x2 + -8x + -16) = 0

Reorder the terms:
(1 + 3x)(x2 + -8x + -16) = 0

Reorder the terms:
(1 + 3x)(-16 + -8x + x2) = 0

Multiply (1 + 3x) * (-16 + -8x + x2)
(1(-16 + -8x + x2) + 3x * (-16 + -8x + x2)) = 0
((-16 * 1 + -8x * 1 + x2 * 1) + 3x * (-16 + -8x + x2)) = 0
((-16 + -8x + 1x2) + 3x * (-16 + -8x + x2)) = 0
(-16 + -8x + 1x2 + (-16 * 3x + -8x * 3x + x2 * 3x)) = 0
(-16 + -8x + 1x2 + (-48x + -24x2 + 3x3)) = 0

Reorder the terms:
(-16 + -8x + -48x + 1x2 + -24x2 + 3x3) = 0

Combine like terms: -8x + -48x = -56x
(-16 + -56x + 1x2 + -24x2 + 3x3) = 0

Combine like terms: 1x2 + -24x2 = -23x2
(-16 + -56x + -23x2 + 3x3) = 0

Solving
-16 + -56x + -23x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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